Dimensional formula of coefficient of friction

Coefficient of friction
[M0 L0 T0]
Written in full: [M⁰ L⁰ T⁰ A⁰ K⁰]

How to derive it

Coefficient of friction = Friction force ÷ Normal reaction

Put in the dimensions of each part: [MLT⁻²] ÷ [MLT⁻²] = [M⁰ L⁰ T⁰].

mass (M)
0
length (L)
0
time (T)
0
current (A)
0
temperature (K)
0

SI unit

The SI unit of coefficient of friction is no unit.

Same dimensions as coefficient of friction

These quantities have exactly the same dimensions, a favourite trick in JEE and NEET "which pair has the same dimensions" questions:

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More from Laws of motion

QuantityFormula
Force[M L T−2]
Momentum[M L T−1]
Impulse[M L T−1]
Weight[M L T−2]