Dimensional formula of impedance

Impedance
[M L2 T−3 A−2]
Written in full: [M¹ L² T⁻³ A⁻² K⁰]

How to derive it

Impedance = Peak voltage ÷ Peak current

Put in the dimensions of each part: [ML²T⁻³A⁻¹] ÷ [A] = [M L² T⁻³ A⁻²].

mass (M)
1
length (L)
2
time (T)
-3
current (A)
-2
temperature (K)
0

SI unit

The SI unit of impedance is ohm (Ω).

Same dimensions as impedance

These quantities have exactly the same dimensions, a favourite trick in JEE and NEET "which pair has the same dimensions" questions:

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