Dimensional formula of lr time constant

LR time constant
[T]
Written in full: [M⁰ L⁰ T¹ A⁰ K⁰]

How to derive it

LR time constant = Inductance ÷ Resistance

Put in the dimensions of each part: [ML²T⁻²A⁻²] ÷ [ML²T⁻³A⁻²] = [T].

mass (M)
0
length (L)
0
time (T)
1
current (A)
0
temperature (K)
0

SI unit

The SI unit of lr time constant is second (s).

Same dimensions as lr time constant

These quantities have exactly the same dimensions, a favourite trick in JEE and NEET "which pair has the same dimensions" questions:

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More from Electromagnetic induction

QuantityFormula
Inductance[M L2 T−2 A−2]
Mutual inductance[M L2 T−2 A−2]
Impedance[M L2 T−3 A−2]