Dimensional formula of mutual inductance

Mutual inductance
[M L2 T−2 A−2]
Written in full: [M¹ L² T⁻² A⁻² K⁰]

How to derive it

Mutual inductance = Induced emf ÷ Rate of change of current

Put in the dimensions of each part: [ML²T⁻³A⁻¹] ÷ [AT⁻¹] = [M L² T⁻² A⁻²].

mass (M)
1
length (L)
2
time (T)
-2
current (A)
-2
temperature (K)
0

SI unit

The SI unit of mutual inductance is henry (H).

Same dimensions as mutual inductance

These quantities have exactly the same dimensions, a favourite trick in JEE and NEET "which pair has the same dimensions" questions:

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More from Electromagnetic induction

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